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46=5x^2
We move all terms to the left:
46-(5x^2)=0
a = -5; b = 0; c = +46;
Δ = b2-4ac
Δ = 02-4·(-5)·46
Δ = 920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{920}=\sqrt{4*230}=\sqrt{4}*\sqrt{230}=2\sqrt{230}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{230}}{2*-5}=\frac{0-2\sqrt{230}}{-10} =-\frac{2\sqrt{230}}{-10} =-\frac{\sqrt{230}}{-5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{230}}{2*-5}=\frac{0+2\sqrt{230}}{-10} =\frac{2\sqrt{230}}{-10} =\frac{\sqrt{230}}{-5} $
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